What is the optimal time complexity of solving Reverse of a number?

The optimized solution achieves a time complexity of O(n) by using sorting, mathematical shortcuts, or hash table lookups.

What is the auxiliary space complexity for Reverse of a number?

The space complexity is O(1) since we only use a minimal/constant amount of extra memory for tracking variables (or auxiliary space if dynamic structures are allocated).

What are the typical edge cases we must handle in Reverse of a number?

Key edge cases include empty collections, negative or large bounds causing integer overflow, arrays with only one element, or inputs where target criteria are not met.

How can we optimize the brute force approach for Reverse of a number?

Brute force methods often inspect all possible combinations. We optimize this by sorting the input list to enable binary search, or tracking processed items in a set to avoid redundant nested loop lookups.

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Python BasicsEasy

Reverse of a number

Learn how to solve the 'Reverse of a number' problem. This detailed resource details brute force and optimized approaches.

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Problem Statement

Easy

Write a function reverse_number(n) that takes a non-negative integer n and returns the integer formed by reversing its digits. Leading zeros in the reversed result should be dropped (e.g., reversing 100 gives 1).

Constraints

•0 <= n <= 10^9

Examples

Example 1

Input

n = 1234

Output

Explanation

Reversing the digits of 1234 gives 4321.

Example 2

Input

n = 100

Output

Explanation

Reversing 100 gives 001, which is 1 as an integer.

Example 3

Input

n = 5

Output

Explanation

A single digit reversed is itself.

Need a Hint?

Use simple arithmetic operators (like modulo `%`, division `//`), conditional checks, or loops to inspect number properties.

Edge Cases to Watch

Empty list or null input variables
Single item lists/arrays
Extremely large input bounds causing integer or stack overflow

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