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Reverse Nodes In K Group

Learn how to solve the 'Reverse Nodes In K Group' problem. This detailed resource details brute force and optimized approaches.

Problem Statement

Easy

Given the head of a linked list, reverse the nodes of the list k at a time, and return the modified list.

k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out nodes, in the end, should remain as it is.

You may not alter the values in the list's nodes, only nodes themselves may be changed.

The linked list is represented as a Python list. Implement a function reverseKGroup(head: list, k: int) -> list.

Constraints
  • The number of nodes in the list is n
  • 1 <= k <= n <= 5000
  • 0 <= Node.val <= 1000

Examples

Example 1
Input
[1,2,3,4,5], 2
Output
[2,1,4,3,5]
Explanation

Reverse in groups of 2: [1,2] becomes [2,1], [3,4] becomes [4,3], and [5] stays as is.

Example 2
Input
[1,2,3,4,5], 3
Output
[3,2,1,4,5]
Explanation

Reverse in groups of 3: [1,2,3] becomes [3,2,1], and [4,5] has fewer than 3 nodes so it stays.

Need a Hint?
Analyze the input constraints. Try sorting first (O(n log n)) or using a hash map/set to track seen elements in O(n) time.
Edge Cases to Watch
  • Empty list or null input variables
  • Single item lists/arrays
  • Extremely large input bounds causing integer or stack overflow

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