What is the optimal time complexity of solving Reverse Bits?

The optimized solution achieves a time complexity of O(n) by using sorting, mathematical shortcuts, or hash table lookups.

What is the auxiliary space complexity for Reverse Bits?

The space complexity is O(1) since we only use a minimal/constant amount of extra memory for tracking variables (or auxiliary space if dynamic structures are allocated).

What are the typical edge cases we must handle in Reverse Bits?

Key edge cases include empty collections, negative or large bounds causing integer overflow, arrays with only one element, or inputs where target criteria are not met.

How can we optimize the brute force approach for Reverse Bits?

Brute force methods often inspect all possible combinations. We optimize this by sorting the input list to enable binary search, or tracking processed items in a set to avoid redundant nested loop lookups.

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Reverse Bits

Learn how to solve the 'Reverse Bits' problem. This detailed resource details brute force and optimized approaches.

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Problem Statement

Easy

Reverse bits of a given 32-bit unsigned integer.

Write a function reverseBits(n: int) -> int.

Constraints

•n must be a 32-bit unsigned integer

Examples

Example 1

Input

n = 43261596

Output

964176192

Explanation

The input binary string 00000010100101000001111010011100 reversed is 00111001011110000010100101000000, representing 964176192.

Need a Hint?

Analyze the input constraints. Try sorting first (O(n log n)) or using a hash map/set to track seen elements in O(n) time.

Edge Cases to Watch

Empty list or null input variables
Single item lists/arrays
Extremely large input bounds causing integer or stack overflow

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