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Reconstruct Itinerary

Learn how to solve the 'Reconstruct Itinerary' problem. This detailed resource details brute force and optimized approaches.

Problem Statement

Easy

You are given a list of airline tickets where tickets[i] = [from_i, to_i] represent the departure and the arrival airports of one flight. Reconstruct the itinerary in order and return it.

All of the tickets belong to a man who departs from 'JFK'. Thus, the itinerary must begin with 'JFK'.

If there are multiple valid itineraries, you should return the itinerary that has the smallest lexical order when read as a single string. For example, the itinerary ['JFK', 'LGA'] has a smaller lexical order than ['JFK', 'LGB'].

You may assume all tickets form at least one valid itinerary. You must use all the tickets once and only once.

Write a function findItinerary(tickets: List[List[str]]) -> List[str].

Constraints
  • 1 <= len(tickets) <= 300
  • tickets[i].length == 2
  • from_i.length == 3
  • to_i.length == 3
  • from_i and to_i consist of uppercase English letters

Examples

Example 1
Input
tickets = [["MUC","LHR"],["JFK","MUC"],["SFO","SJC"],["LHR","SFO"]]
Output
["JFK","MUC","LHR","SFO","SJC"]
Explanation

The only valid itinerary is JFK -> MUC -> LHR -> SFO -> SJC.

Example 2
Input
tickets = [["JFK","SFO"],["JFK","ATL"],["SFO","ATL"],["ATL","JFK"],["ATL","SFO"]]
Output
["JFK","ATL","JFK","SFO","ATL","SFO"]
Explanation

Another possible reconstruction is JFK -> SFO -> ATL -> JFK -> ATL -> SFO, but it is larger lexically.

Need a Hint?
Represent graph node connections as an adjacency list/matrix, then use standard BFS or DFS graph traversal.
Edge Cases to Watch
  • Empty list or null input variables
  • Single item lists/arrays
  • Extremely large input bounds causing integer or stack overflow

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