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Pow(x, n)
Learn how to solve the 'Pow(x, n)' problem. This detailed resource details brute force and optimized approaches.
Problem Statement
Easy
Implement pow(x, n), which calculates x raised to the power n (i.e., x^n).
Implement a function myPow(x: float, n: int) -> float.
Constraints
- •-100.0 < x < 100.0
- •-2^31 <= n <= 2^31 - 1
- •n is an integer
- •Either x is not zero or n > 0
- •-10^4 <= x^n <= 10^4
Examples
Example 1
Input
2.00000, 10
Output
1024.00000
Explanation
2^10 = 1024.
Example 2
Input
2.10000, 3
Output
9.26100
Explanation
2.1^3 = 9.261.
Example 3
Input
2.00000, -2
Output
0.25000
Explanation
2^(-2) = 1/(2^2) = 1/4 = 0.25.
Need a Hint?
Analyze the input constraints. Try sorting first (O(n log n)) or using a hash map/set to track seen elements in O(n) time.
Edge Cases to Watch
- Empty list or null input variables
- Single item lists/arrays
- Extremely large input bounds causing integer or stack overflow
Ready to Solve?
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