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Pow(x, n)

Learn how to solve the 'Pow(x, n)' problem. This detailed resource details brute force and optimized approaches.

Problem Statement

Easy

Implement pow(x, n), which calculates x raised to the power n (i.e., x^n).

Implement a function myPow(x: float, n: int) -> float.

Constraints
  • -100.0 < x < 100.0
  • -2^31 <= n <= 2^31 - 1
  • n is an integer
  • Either x is not zero or n > 0
  • -10^4 <= x^n <= 10^4

Examples

Example 1
Input
2.00000, 10
Output
1024.00000
Explanation

2^10 = 1024.

Example 2
Input
2.10000, 3
Output
9.26100
Explanation

2.1^3 = 9.261.

Example 3
Input
2.00000, -2
Output
0.25000
Explanation

2^(-2) = 1/(2^2) = 1/4 = 0.25.

Need a Hint?
Analyze the input constraints. Try sorting first (O(n log n)) or using a hash map/set to track seen elements in O(n) time.
Edge Cases to Watch
  • Empty list or null input variables
  • Single item lists/arrays
  • Extremely large input bounds causing integer or stack overflow

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