Pow(x, n)
Detailed guide and Python implementation for the 'Pow(x, n)' problem.
Problem Statement
Implement pow(x, n), which calculates x raised to the power n (i.e., x^n).
Implement a function myPow(x: float, n: int) -> float.
- •-100.0 < x < 100.0
- •-2^31 <= n <= 2^31 - 1
- •n is an integer
- •Either x is not zero or n > 0
- •-10^4 <= x^n <= 10^4
Examples
2.00000, 10
1024.00000
2^10 = 1024.
2.10000, 3
9.26100
2.1^3 = 9.261.
2.00000, -2
0.25000
2^(-2) = 1/(2^2) = 1/4 = 0.25.
Need a Hint?
Edge Cases to Watch
- Empty input structures
- Single element inputs
- Large numerical bounds
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