What is the optimal time complexity of solving Palindrome Partitioning?

The optimized solution achieves a time complexity of O(n) by using sorting, mathematical shortcuts, or hash table lookups.

What is the auxiliary space complexity for Palindrome Partitioning?

The space complexity is O(1) since we only use a minimal/constant amount of extra memory for tracking variables (or auxiliary space if dynamic structures are allocated).

What are the typical edge cases we must handle in Palindrome Partitioning?

Key edge cases include empty collections, negative or large bounds causing integer overflow, arrays with only one element, or inputs where target criteria are not met.

How can we optimize the brute force approach for Palindrome Partitioning?

Brute force methods often inspect all possible combinations. We optimize this by sorting the input list to enable binary search, or tracking processed items in a set to avoid redundant nested loop lookups.

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Competitive ProgrammingEasy

Palindrome Partitioning

Learn how to solve the 'Palindrome Partitioning' problem. This detailed resource details brute force and optimized approaches.

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Problem Statement

Easy

Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s.

Implement a function partition(s: str) -> list.

Constraints

•1 <= s.length <= 16
•s contains only lowercase English letters

Examples

Example 1

Input

"aab"

Output

[["a","a","b"],["aa","b"]]

Explanation

"a","a","b" are all palindromes. "aa" is a palindrome and "b" is a palindrome. These are the only two valid partitions.

Example 2

Input

"a"

Output

[["a"]]

Explanation

A single character is always a palindrome.

Need a Hint?

Define subproblem states, establish the recurrence relation, and use memoization (top-down) or tabulation (bottom-up).

Edge Cases to Watch

Empty list or null input variables
Single item lists/arrays
Extremely large input bounds causing integer or stack overflow

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