Octal to Binary conversion
Detailed guide and Python implementation for the 'Octal to Binary conversion' problem.
1. Concept Overview
The 'Octal to Binary conversion' problem is a key challenge in the Numbers section.
This implementation focuses on easy-level logic in Python.
We prioritize technical accuracy and code readability in our provided solutions.
2. Real-World Applications
3. Visual Intuition
Visualizing the logic flow for Octal to Binary conversion.
4. Prerequisites
5. Step-by-Step Thinking
1. Understand the problem
Read the problem statement for Octal to Binary conversion carefully.
2. Formulate brute force
Draft a simple iterative solution.
3. Identify inefficiency
Look for redundant calculations.
4. Optimize search path
Use hashing or sorting to speed up the process.
5. Final Implementation
Clean up the code for production standards.
Problem Statement
Write a function octal_to_binary(octal_str) that takes a string representing an octal number (base-8, digits 0-7) and returns a string representing its binary (base-2) equivalent. Do not include leading zeros in the output (except for input '0').
Hint: Convert each octal digit to its 3-bit binary equivalent and concatenate.
- •1 <= len(octal_str) <= 10
- •octal_str contains only digits '0' through '7'
Examples
octal_to_binary('12')'1010'
1 = 001, 2 = 010. Concatenate: 001010. Remove leading zeros: 1010.
octal_to_binary('77')'111111'
7 = 111, 7 = 111. Concatenate: 111111.
octal_to_binary('312')'11001010'
3 = 011, 1 = 001, 2 = 010. Concatenate: 011001010. Remove leading zero: 11001010.
Need a Hint?
Edge Cases to Watch
- Empty input structures
- Single element inputs
- Large numerical bounds
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Interview Insights & Variations
Complexity Analysis Breakdown
Why Time: Directly evaluates all possibilities.
Why Space: Uses standard local memory.
Why Time: Optimized paths reduce total operations.
Why Space: May trade memory for speed.
Optimized Solution Python Code
Optimized Solution Python Code
def octal_to_binary_opt(octal_str):
octal_str = str(octal_str)
binary = ""
mapping = {'0':'000', '1':'001', '2':'010', '3':'011',
'4':'100', '5':'101', '6':'110', '7':'111'}
for digit in octal_str:
binary += mapping[digit]
return binary.lstrip('0') or '0'Brute Force Code (Spoiler Guarded)
Brute Force Code (Spoiler Guarded)
def octal_to_binary_brute(octal_str):
decimal = int(str(octal_str), 8)
return bin(decimal)[2:]Algorithm Pattern Checklist
When dealing with Numbers data patterns.
Core Prerequisites
Revision Key Notes
Common Mistakes & Pitfalls
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