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Min Stack

Learn how to solve the 'Min Stack' problem. This detailed resource details brute force and optimized approaches.

Problem Statement

Easy

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

Implement the MinStack class:

- MinStack() initializes the stack object.

- push(val: int) pushes the element val onto the stack.

- pop() removes the element on the top of the stack.

- top() -> int gets the top element of the stack.

- getMin() -> int retrieves the minimum element in the stack.

You must implement a solution with O(1) time complexity for each function.

Constraints
  • -2^31 <= val <= 2^31 - 1
  • Methods pop, top, and getMin are always called on non-empty stacks
  • At most 3 * 10^4 calls will be made to push, pop, top, and getMin

Examples

Example 1
Input
["MinStack", "push", "push", "push", "getMin", "pop", "top", "getMin"]
[[], [-2], [0], [-3], [], [], [], []]
Output
[None, None, None, None, -3, None, 0, -2]
Explanation

MinStack created. Push -2, 0, -3. getMin() returns -3. Pop removes -3. top() returns 0. getMin() returns -2.

Need a Hint?
Analyze the input constraints. Try sorting first (O(n log n)) or using a hash map/set to track seen elements in O(n) time.
Edge Cases to Watch
  • Empty list or null input variables
  • Single item lists/arrays
  • Extremely large input bounds causing integer or stack overflow

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