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Invert Binary Tree

Learn how to solve the 'Invert Binary Tree' problem. This detailed resource details brute force and optimized approaches.

Problem Statement

Medium

Given the root of a binary tree, invert the tree, and return its root.

Inverting a binary tree means swapping the left and right children of every node in the tree.

The tree is represented as a level-order list where None represents a missing node. Implement a function invertTree(root: list) -> list that returns the inverted tree in level-order.

Constraints
  • The number of nodes in the tree is in the range [0, 100]
  • -100 <= Node.val <= 100

Examples

Example 1
Input
[4,2,7,1,3,6,9]
Output
[4,7,2,9,6,3,1]
Explanation

The root stays 4. Its children swap: left becomes 7, right becomes 2. Their children also swap recursively.

Example 2
Input
[2,1,3]
Output
[2,3,1]
Explanation

The root stays 2. Left child 1 and right child 3 are swapped.

Example 3
Input
[]
Output
[]
Explanation

An empty tree inverted is still empty.

Need a Hint?
Perform a recursive tree traversal (DFS) or level-order traversal (BFS) using a queue/stack.
Edge Cases to Watch
  • Empty list or null input variables
  • Single item lists/arrays
  • Extremely large input bounds causing integer or stack overflow

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