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Finding number of integers which has exactly x divisors

Learn how to solve the 'Finding number of integers which has exactly x divisors' problem. This detailed resource details brute force and optimized approaches.

Problem Statement

Easy

Write a function count_with_x_divisors(n, x) that takes two positive integers n and x, and returns the count of integers in the range [1, n] (inclusive) that have exactly x divisors.

A divisor of a number k is any integer that divides k evenly. For example, divisors of 6 are 1, 2, 3, 6 (4 divisors).

Constraints
  • 1 <= n <= 1000
  • 1 <= x <= 50

Examples

Example 1
Input
count_with_x_divisors(10, 2)
Output
4
Explanation

Numbers from 1 to 10 with exactly 2 divisors (i.e., prime numbers): 2, 3, 5, 7. That's 4 numbers.

Example 2
Input
count_with_x_divisors(10, 1)
Output
1
Explanation

Only the number 1 has exactly 1 divisor.

Example 3
Input
count_with_x_divisors(20, 4)
Output
5
Explanation

Numbers from 1-20 with exactly 4 divisors: 6(1,2,3,6), 8(1,2,4,8), 10(1,2,5,10), 14(1,2,7,14), 15(1,3,5,15). That's 5 numbers.

Need a Hint?
Use simple arithmetic operators (like modulo `%`, division `//`), conditional checks, or loops to inspect number properties.
Edge Cases to Watch
  • Empty list or null input variables
  • Single item lists/arrays
  • Extremely large input bounds causing integer or stack overflow

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