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Find The Duplicate Number

Learn how to solve the 'Find The Duplicate Number' problem. This detailed resource details brute force and optimized approaches.

Problem Statement

Easy

Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive.

There is only one repeated number in nums, return this repeated number.

You must solve the problem without modifying the array nums and using only constant extra space.

Implement a function findDuplicate(nums: list) -> int that returns the duplicate number.

Constraints
  • 1 <= n <= 100000
  • nums.length == n + 1
  • 1 <= nums[i] <= n
  • There is only one repeated number in nums, but it could be repeated more than once

Examples

Example 1
Input
[1,3,4,2,2]
Output
2
Explanation

The duplicate number is 2. It appears twice in the array.

Example 2
Input
[3,1,3,4,2]
Output
3
Explanation

The duplicate number is 3. It appears twice in the array.

Example 3
Input
[3,3,3,3,3]
Output
3
Explanation

The duplicate number is 3. It appears five times.

Need a Hint?
Analyze the input constraints. Try sorting first (O(n log n)) or using a hash map/set to track seen elements in O(n) time.
Edge Cases to Watch
  • Empty list or null input variables
  • Single item lists/arrays
  • Extremely large input bounds causing integer or stack overflow

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