Find Minimum In Rotated Sorted Array
Learn how to solve the 'Find Minimum In Rotated Sorted Array' problem. This detailed resource details brute force and optimized approaches.
Problem Statement
Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2] if it was rotated 4 times.
Notice that rotating an array [a[0], a[1], ..., a[n-1]] 1 time results in [a[n-1], a[0], a[1], ..., a[n-2]].
Given the sorted rotated array nums of unique elements, return the minimum element of this array.
You must write an algorithm that runs in O(log n) time.
Write a function findMin(nums: List[int]) -> int.
- •n == len(nums)
- •1 <= n <= 5000
- •-5000 <= nums[i] <= 5000
- •All integers in nums are unique
- •nums is sorted and rotated between 1 and n times
Examples
nums = [3, 4, 5, 1, 2]
1
The original array was [1,2,3,4,5] rotated 3 times. The minimum is 1.
nums = [4, 5, 6, 7, 0, 1, 2]
0
The original array was [0,1,2,4,5,6,7] rotated 4 times. The minimum is 0.
nums = [11, 13, 15, 17]
11
Array is not rotated (or rotated n times). The minimum is the first element.
Need a Hint?
Edge Cases to Watch
- Empty list or null input variables
- Single item lists/arrays
- Extremely large input bounds causing integer or stack overflow
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