Decimal to Hexadecimal Conversion
Detailed guide and Python implementation for the 'Decimal to Hexadecimal Conversion' problem.
1. Concept Overview
The 'Decimal to Hexadecimal Conversion' problem is a key challenge in the Numbers section.
This implementation focuses on easy-level logic in Python.
We prioritize technical accuracy and code readability in our provided solutions.
2. Real-World Applications
3. Visual Intuition
Visualizing the logic flow for Decimal to Hexadecimal Conversion.
4. Prerequisites
5. Step-by-Step Thinking
1. Understand the problem
Read the problem statement for Decimal to Hexadecimal Conversion carefully.
2. Formulate brute force
Draft a simple iterative solution.
3. Identify inefficiency
Look for redundant calculations.
4. Optimize search path
Use hashing or sorting to speed up the process.
5. Final Implementation
Clean up the code for production standards.
Problem Statement
Write a function decimal_to_hex(n) that takes a non-negative integer n and returns a string representing its hexadecimal (base-16) equivalent using uppercase letters (A-F). Do not include leading zeros (except for input 0, which should return '0').
To convert, repeatedly divide by 16 and collect remainders (using A=10, B=11, ..., F=15) in reverse order.
- •0 <= n <= 10^6
Examples
decimal_to_hex(255)
'FF'
255 ÷ 16 = 15 remainder 15. 15 = F. So result is FF.
decimal_to_hex(26)
'1A'
26 ÷ 16 = 1 remainder 10. 10 = A. Result: 1A.
decimal_to_hex(100)
'64'
100 ÷ 16 = 6 remainder 4. Result: 64.
Need a Hint?
Edge Cases to Watch
- Empty input structures
- Single element inputs
- Large numerical bounds
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Interview Insights & Variations
Complexity Analysis Breakdown
Why Time: Directly evaluates all possibilities.
Why Space: Uses standard local memory.
Why Time: Optimized paths reduce total operations.
Why Space: May trade memory for speed.
Optimized Solution Python Code
Optimized Solution Python Code
def decimal_to_hex_opt(n):
return hex(n)[2:].upper()Brute Force Code (Spoiler Guarded)
Brute Force Code (Spoiler Guarded)
def decimal_to_hex_brute(n):
if n == 0: return "0"
hex_chars = "0123456789ABCDEF"
hex_str = ""
while n > 0:
hex_str = hex_chars[n % 16] + hex_str
n //= 16
return hex_strAlgorithm Pattern Checklist
When dealing with Numbers data patterns.
Core Prerequisites
Revision Key Notes
Common Mistakes & Pitfalls
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