Construct Binary Tree
Learn how to solve the 'Construct Binary Tree' problem. This detailed resource details brute force and optimized approaches.
Problem Statement
Given two integer arrays preorder and inorder where preorder is the preorder traversal of a binary tree and inorder is the inorder traversal of the same tree, construct and return the binary tree.
The tree should be returned as a level-order list. Implement a function buildTree(preorder: list, inorder: list) -> list.
- •1 <= preorder.length <= 3000
- •inorder.length == preorder.length
- •-3000 <= preorder[i], inorder[i] <= 3000
- •preorder and inorder consist of unique values
- •Each value of inorder also appears in preorder
- •preorder is guaranteed to be the preorder traversal of the tree
- •inorder is guaranteed to be the inorder traversal of the tree
Examples
[3,9,20,15,7], [9,3,15,20,7]
[3,9,20,None,None,15,7]
Preorder: root is 3. In inorder, 9 is to the left of 3 (left subtree) and [15,20,7] is to the right (right subtree). Recursively build: left subtree is just [9], right subtree has root 20 with children 15 and 7.
[-1], [-1]
[-1]
Single node tree.
Need a Hint?
Edge Cases to Watch
- Empty list or null input variables
- Single item lists/arrays
- Extremely large input bounds causing integer or stack overflow
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