Coin Change
Learn how to solve the 'Coin Change' problem. This detailed resource details brute force and optimized approaches.
Problem Statement
You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money.
Return the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins, return -1.
You may assume that you have an infinite number of each kind of coin.
Write a function coinChange(coins: List[int], amount: int) -> int.
- •1 <= len(coins) <= 12
- •1 <= coins[i] <= 2^31 - 1
- •0 <= amount <= 10^4
Examples
coins = [1,2,5], amount = 11
3
11 = 5 + 5 + 1
coins = [2], amount = 3
-1
3 cannot be formed using only coins of denomination 2.
coins = [1], amount = 0
0
No coins are needed to make amount 0.
Need a Hint?
Edge Cases to Watch
- Empty list or null input variables
- Single item lists/arrays
- Extremely large input bounds causing integer or stack overflow
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