Binary to Octal conversion
Detailed guide and Python implementation for the 'Binary to Octal conversion' problem.
1. Concept Overview
The 'Binary to Octal conversion' problem is a key challenge in the Numbers section.
This implementation focuses on easy-level logic in Python.
We prioritize technical accuracy and code readability in our provided solutions.
2. Real-World Applications
3. Visual Intuition
Visualizing the logic flow for Binary to Octal conversion.
4. Prerequisites
5. Step-by-Step Thinking
1. Understand the problem
Read the problem statement for Binary to Octal conversion carefully.
2. Formulate brute force
Draft a simple iterative solution.
3. Identify inefficiency
Look for redundant calculations.
4. Optimize search path
Use hashing or sorting to speed up the process.
5. Final Implementation
Clean up the code for production standards.
Problem Statement
Write a function binary_to_octal(binary_str) that takes a string representing a binary number and returns a string representing its octal (base-8) equivalent. Do not include leading zeros in the output (except for input '0').
Hint: Group the binary digits into groups of 3 from right to left, then convert each group to its octal digit.
- •1 <= len(binary_str) <= 20
- •binary_str contains only '0' and '1'
Examples
binary_to_octal('1010')'12'
Group from right: 001 010. 001 = 1, 010 = 2. So octal is 12. (Binary 1010 = Decimal 10 = Octal 12.)
binary_to_octal('111111')'77'
Group: 111 111. 111 = 7, 111 = 7. Octal is 77. (Binary 111111 = Decimal 63 = Octal 77.)
binary_to_octal('11001010')'312'
Group from right: 011 001 010. 011=3, 001=1, 010=2. Octal is 312. (Binary 11001010 = Decimal 202 = Octal 312.)
Need a Hint?
Edge Cases to Watch
- Empty input structures
- Single element inputs
- Large numerical bounds
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Interview Insights & Variations
Complexity Analysis Breakdown
Why Time: Directly evaluates all possibilities.
Why Space: Uses standard local memory.
Why Time: Optimized paths reduce total operations.
Why Space: May trade memory for speed.
Optimized Solution Python Code
Optimized Solution Python Code
def binary_to_octal_opt(binary_str):
binary_str = str(binary_str)
while len(binary_str) % 3 != 0:
binary_str = '0' + binary_str
octal = ""
for i in range(0, len(binary_str), 3):
bits = binary_str[i:i+3]
octal += str(int(bits, 2))
return octal.lstrip('0') or '0'Brute Force Code (Spoiler Guarded)
Brute Force Code (Spoiler Guarded)
def binary_to_octal_brute(binary_str):
decimal = int(str(binary_str), 2)
return oct(decimal)[2:]Algorithm Pattern Checklist
When dealing with Numbers data patterns.
Core Prerequisites
Revision Key Notes
Common Mistakes & Pitfalls
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