Python 基础知识简单

根据另一个数组排序

“根据另一个数组排序”问题的详细指南和 Python 实现。

问题陈述

简单

编写一个函数 sort_by_order(arr1, arr2),根据 arr2 定义的顺序对 arr1 的元素进行排序。 arr1 中出现在 arr2 中的元素应按照它们在 arr2 中出现的顺序排在前面。不在 arr2 中的元素应按排序(升序)顺序出现在末尾。

约束条件
  • 1 <= len(arr1) <= 10^5
  • 0 <= len(arr2) <= 100
  • Elements of arr2 are distinct

示例

Example 1
Input
arr1 = [2, 1, 2, 5, 7, 1, 9, 3, 6, 8, 8], arr2 = [2, 1, 8, 3]
Output
[2, 2, 1, 1, 8, 8, 3, 5, 6, 7, 9]
Explanation

First all 2s, then 1s, then 8s, then 3s (order from arr2). Remaining [5,6,7,9] sorted ascending.

Example 2
Input
arr1 = [4, 5, 6], arr2 = [6, 4]
Output
[6, 4, 5]
Explanation

6 first, then 4 (per arr2 order). 5 is not in arr2, goes at end.

Example 3
Input
arr1 = [1, 2, 3], arr2 = []
Output
[1, 2, 3]
Explanation

No order specified, so sort ascending.

Need a Hint?
考虑使用特定于数组的数据结构,例如集合或堆。
Edge Cases to Watch
  • 空输入结构
  • 单元素输入
  • 大数值范围

准备好解决了吗?

Open the problem in PyRun's browser-based Python editor. Your code runs fully offline — no server required.

在编辑器中打开
Found this breakdown helpful?

PyRun is built and maintained by an independent solo developer. If this helped your interview prep, consider buying a coffee!

Buy me a coffee

推荐的 Python 资源

通过相关的交互式教程、备忘单和代码比较来扩展您的知识。